• poke@sh.itjust.works
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    5 months ago

    6 potential pairs, but you can only ever submit two pairs at a time without reusing any cards.

  • bisby@lemmy.world
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    5 months ago

    Looks like n of a kind results in (n^2-n)/2 pairs. (Which is the same as the sum of 1…(n-1))

    5 of a kind would be 10 pairs. 6 of a kind would be 15, etc