£36.85m ($46.75m) will be shared between claimants who claim that they were unfairly paid, and £7.1m ($9.1m) will cover associated legal fees.

That is a lot of money. Any idea how many they are?

I am Turkish. They are doing this becuse it is one of the weird shows of extreme right wing

!interestingasfuck

Chill man, getting downvoted sometimes means people disagree with you, as you said; not that your comment was shitty.

What is 'pad?

I have been using Firefox with ublock for a very long time. I forgot how they looked like

Mind that this is not encrypted. You can try infomaniak.com as well. It is the same under Swiss privacy laws.

https://personal.onlyoffice.com/

Garuda linux has a gamong edition that has a lot of gaming related packages are preinstalled

Goodbot, poor Reedditorz missing this shit now, right?

Inside lutris sidebar at the bottom, you can install the latest version. Lutris8 was updated last two years ago or so

Maybe you can cjeck garuda gnu linux

Did you install lol version of wine in Lutris?

Everything is perfect with heroiclauncher except for the redists. You have to find them yourself then install them manually using winetricks probably

Work fine for me on plasma wayland. Even the system settings has an option for it

Without condition would be more technically correct term but yes

U can also try !sp

A/100×B=A×B/100

Just count the number of possibilities. If you change there there two possible first choices to win + if you do not change 1 possible choice to win = 3. If you change there is one possible first choice to lose + if you do not change there two possible first choices to lose=3 P(x1)=P(x1’) = 3/6

First, fuck you! I couldn’t sleep. The possibility to win the car when you change is the possibility of your first choice to be goat, which is 2/3, because you only win when your first choice is goat when you always change.

x1: you win

x2: you change

x3: you pick goat at first choice

P(x1|x2,x3)=1 P(x1)=1/2 P(x3)=2/3 P(x2)=1/2

P(x1|x2) =?

Chain theory of probability:

P(x1,x2,x3)=P(x3|x1,x2)P(x1|x2)P(x2)=P(x1|x2,x3)P(x2|x3)P(x3)

From Bayes theorem: P(x3|x1,x2)= P(x1|x2,x3)P(x2)/P(x1) =1

x2 and x3 are independent P(x2|x3)=P(x2)

P(x1| x2)=P(x3)=2/3 P(x2|x1)=P(x1|x2)P(x2)/P(X1)=P(x1|x2)

P(x1=1|x2=0) = 1- P(x1=1|x2=1) = 1\3 is the probability to win if u do not change.